(4a+B-C)^2, (5x-Y+8)^2

(4a+b-c)^2

(5x-y+8)^2

 

Answer:

(4a+b−c)²

=(4a+b−c)(4a+b−c)

=(4a)(4a)+(4a)(b)+(4a)(−c)+(b)(4a)+(b)(b)+(b)(−c)+(−c)(4a)+(−c)(b)+(−c)(−c)

=16a²+4ab−4ac+4ab+b²−bc−4ac−bc+c²

=16a²+8ab−8ac+b²−2bc+c²

(5x−y+8)²

=(5x−y+8)(5x−y+8)

=(5x)(5x)+(5x)(−y)+(5x)(8)+(−y)(5x)+(−y)(−y)+(−y)(8)+(8)(5x)+(8)(−y)+(8)(8)

=25x²−5xy+40x−5xy+y²−8y+40x−8y+64

=25x²−10xy+y²+80x−16y+64

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